If a pendulum is taken to Mars, how would its period change?
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A) First, we must determine the relationship between the pendulum's period and gravity.
The period (P) of a pendulum of length l is a time, so
=T
if P α lagb
T=[l]a[g]b
T=La(L/T2)b
Thus, a=1/2 and b=-1/2
P α √(l/g)
- TM/TE=√(gE/gM)
TM=TE√(gE/gM)
TM=(4s)√3
TM~7s
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